What is the answer to 4^{log_{2}(2x)}=36 ?

The answer to 4^{log_{2}(2x)}=36 is x=2^{(ln(3))/(ln(2))}

Solve for x: 4^{log_{2}(2x)}=36

The solution is x=2^{(ln(3))/(ln(2))}

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4^{l o g_{2} (2 x)} = 36

x = 2^{\frac{l n ( 3 )}{l n ( 2 )}}

Decimal Notation

x = 3

Solution steps

4^{l o g_{2} (2 x)} = 36

Apply exponent rules

lo g_{2} (2 x) ln (4) = ln (36)

Solve

lo g_{2} (2 x) ln (4) = ln (36) : x = 2^{\frac{l n ( 3 )}{l n ( 2 )}}

x = 2^{\frac{l n ( 3 )}{l n ( 2 )}}

k^{x + 1} \cdot k^{x - 1} = k^{10}

(3^{x}) + (3^{x}) = 54

\frac{( 2 ^{n^{2}} )}{( 2 ^{n} \cdot 2 ^{6} )} = 1

x, 3^{x} - 3^{y} = 19602

e^{x} - e^{- x} = 2

What is the answer to 4^{log_{2}(2x)}=36 ?
The answer to 4^{log_{2}(2x)}=36 is x=2^{(ln(3))/(ln(2))}
Solve for x: 4^{log_{2}(2x)}=36
The solution is x=2^{(ln(3))/(ln(2))}