What is the answer to solvefor x,3^x-3^y=19602 ?

The answer to solvefor x,3^x-3^y=19602 is x=(ln(19602+3^y))/(ln(3))

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solvefor x,3^x-3^y=19602

solve for

x, 3^{x} - 3^{y} = 19602

x = \frac{ln ( 19602 + 3 ^{y} )}{ln ( 3 )}

Solution steps

3^{x} - 3^{y} = 19602

Move

3^{y}

to the right side

3^{x} = 19602 + 3^{y}

Apply exponent rules

x ln (3) = ln (19602 + 3^{y})

Solve

x ln (3) = ln (19602 + 3^{y}) : x = \frac{ln ( 19602 + 3 ^{y} )}{ln ( 3 )}

x = \frac{ln ( 19602 + 3 ^{y} )}{ln ( 3 )}

e^{x} - e^{- x} = 2

7^{x^{2} + 2 x - 3} = 1

3^{x + 5} = 7^{x}

3^{2 x - 1} = 7^{x + 1}

n, (1 + i)^{n} = 1.42

What is the answer to solvefor x,3^x-3^y=19602 ?
The answer to solvefor x,3^x-3^y=19602 is x=(ln(19602+3^y))/(ln(3))