What is the answer to 1/(2^x)+1/(2^x)+1/(2^x)=3 ?

The answer to 1/(2^x)+1/(2^x)+1/(2^x)=3 is x=0

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

1/(2^x)+1/(2^x)+1/(2^x)=3

\frac{1}{2 ^{x}} + \frac{1}{2 ^{x}} + \frac{1}{2 ^{x}} = 3

x = 0

Solution steps

\frac{1}{2 ^{x}} + \frac{1}{2 ^{x}} + \frac{1}{2 ^{x}} = 3

Apply exponent rules

- x ln (2) = ln (1)

Solve

- x ln (2) = ln (1) : x = 0

x = 0

Verify Solutions:

x = 0

True

The solution is

x = 0

(2^{x})^{6} = (2^{9})^{2}

4^{x - 1} \cdot (0.5)^{3 - 2 x} = (\frac{1}{8})^{x}

3^{1 - x} = \frac{1}{( 3 )}

4 \cdot 3^{x} = 324

5^{x} + 5^{x - 1} + 5^{x - 2} = 155

What is the answer to 1/(2^x)+1/(2^x)+1/(2^x)=3 ?
The answer to 1/(2^x)+1/(2^x)+1/(2^x)=3 is x=0
Solve for x: 1/(2^x)+1/(2^x)+1/(2^x)=3
The solution is x=0