What is the answer to 3^{1-x}= 1/((sqrt(3))) ?

The answer to 3^{1-x}= 1/((sqrt(3))) is x= 3/2

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3^{1-x}= 1/((sqrt(3)))

3^{1 - x} = \frac{1}{( 3 )}

x = \frac{3}{2}

Decimal Notation

x = 1.5

Solution steps

3^{1 - x} = \frac{1}{( 3 )}

Apply exponent rules

1 - x = - \frac{1}{2}

Solve

1 - x = - \frac{1}{2} : x = \frac{3}{2}

x = \frac{3}{2}

4 \cdot 3^{x} = 324

5^{x} + 5^{x - 1} + 5^{x - 2} = 155

2^{x - 1} = 35

a, x^{a} = x^{11} + x^{10}

12 = \frac{100}{2 ^{\frac{x}{10}}}

What is the answer to 3^{1-x}= 1/((sqrt(3))) ?
The answer to 3^{1-x}= 1/((sqrt(3))) is x= 3/2
Solve for x: 3^{1-x}= 1/((sqrt(3)))
The solution is x= 3/2