What is the answer to solvefor a,x^a=x^{11}+x^{10} ?

The answer to solvefor a,x^a=x^{11}+x^{10} is a=(ln(x^{11}+x^{10}))/(ln(x))

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solvefor a,x^a=x^{11}+x^{10}

solve for

a, x^{a} = x^{11} + x^{10}

a = \frac{ln ( x ^{11} + x ^{10} )}{ln ( x )}

Solution steps

x^{a} = x^{11} + x^{10}

Apply exponent rules

a ln (x) = ln (x^{11} + x^{10})

Solve

a ln (x) = ln (x^{11} + x^{10}) : a = \frac{ln ( x ^{11} + x ^{10} )}{ln ( x )}

a = \frac{ln ( x ^{11} + x ^{10} )}{ln ( x )}

12 = \frac{100}{2 ^{\frac{x}{10}}}

2^{x} = x

x, 2 a^{x + 1} + 4^{y + 1} = 96

2^{y} = 1.59

4^{3 x - 1} = 3 (5^{x})

What is the answer to solvefor a,x^a=x^{11}+x^{10} ?
The answer to solvefor a,x^a=x^{11}+x^{10} is a=(ln(x^{11}+x^{10}))/(ln(x))