What is the answer to x^2=4^x ?

The answer to x^2=4^x is x=-(\W_{0}(ln(2)))/(ln(2))

The solution is x=-(\W_{0}(ln(2)))/(ln(2))

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x^2=4^x

x^{2} = 4^{x}

x = - \frac{W _{0} ( ln ( 2 ) )}{ln ( 2 )}

Decimal Notation

x = - 0.64118 \dots

Solution steps

x^{2} = 4^{x}

Take both sides of the equation to the power of

\frac{1}{2}

(x^{2})^{\frac{1}{2}} = (4^{x})^{\frac{1}{2}}

Simplify

(x^{2})^{\frac{1}{2}} : ∣ x ∣

Simplify

(4^{x})^{\frac{1}{2}} : 2^{x}

Solve

∣ x ∣ = 2^{x} : x = - \frac{W _{0} ( ln ( 2 ) )}{ln ( 2 )}

x = - \frac{W _{0} ( ln ( 2 ) )}{ln ( 2 )}

3^{x} - 3^{- x} + 2 = 0

10 x - 20.89 \cdot e^{\frac{- x}{( 2478.82 )}} = 0

4^{x} = 5^{x + 1}

3^{x^{2} - 1} = 134

x^{x} = 100

What is the answer to x^2=4^x ?
The answer to x^2=4^x is x=-(\W_{0}(ln(2)))/(ln(2))
Solve for x: x^2=4^x
The solution is x=-(\W_{0}(ln(2)))/(ln(2))