What is the answer to 17^{x-6}=11^{-5x} ?

The answer to 17^{x-6}=11^{-5x} is x=(6ln(17))/(ln(17)+5ln(11))

Solve for x: 17^{x-6}=11^{-5x}

The solution is x=(6ln(17))/(ln(17)+5ln(11))

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1 7^{x - 6} = 1 1^{- 5 x}

x = \frac{6 ln ( 17 )}{ln ( 17 ) + 5 ln ( 11 )}

Decimal Notation

x = 1.14684 \dots

Solution steps

1 7^{x - 6} = 1 1^{- 5 x}

Apply exponent rules

(x - 6) ln (17) = - 5 x ln (11)

Solve

(x - 6) ln (17) = - 5 x ln (11) : x = \frac{6 ln ( 17 )}{ln ( 17 ) + 5 ln ( 11 )}

x = \frac{6 ln ( 17 )}{ln ( 17 ) + 5 ln ( 11 )}

3^{l o g_{3} (x - 2)} = lo g_{6} (216)

3^{x + 1} = \frac{1}{( 2 7 ^{x - 3} )}

5^{x} - 24 = \frac{25}{5 ^{x}}

4 (3^{2 x}) = e^{x}

3^{x + 2} = 3^{1 - x} - 26

What is the answer to 17^{x-6}=11^{-5x} ?
The answer to 17^{x-6}=11^{-5x} is x=(6ln(17))/(ln(17)+5ln(11))
Solve for x: 17^{x-6}=11^{-5x}
The solution is x=(6ln(17))/(ln(17)+5ln(11))