What is the answer to 3^{3x-1}=2^{x+3} ?

The answer to 3^{3x-1}=2^{x+3} is x=(ln(24))/(3ln(3)-ln(2))

Solve for x: 3^{3x-1}=2^{x+3}

The solution is x=(ln(24))/(3ln(3)-ln(2))

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3^{3 x - 1} = 2^{x + 3}

x = \frac{ln ( 24 )}{3 ln ( 3 ) - ln ( 2 )}

Decimal Notation

x = 1.22106 \dots

Solution steps

3^{3 x - 1} = 2^{x + 3}

Apply exponent rules

(3 x - 1) ln (3) = (x + 3) ln (2)

Solve

(3 x - 1) ln (3) = (x + 3) ln (2) : x = \frac{ln ( 24 )}{3 ln ( 3 ) - ln ( 2 )}

x = \frac{ln ( 24 )}{3 ln ( 3 ) - ln ( 2 )}

1 0^{x - 1} = 1000

3^{x + 1} = 4^{x - 1}

2^{x} = \frac{1}{32}

2^{x} + 4^{x} = 3

2^{x} = 4^{2 x - 1}

What is the answer to 3^{3x-1}=2^{x+3} ?
The answer to 3^{3x-1}=2^{x+3} is x=(ln(24))/(3ln(3)-ln(2))
Solve for x: 3^{3x-1}=2^{x+3}
The solution is x=(ln(24))/(3ln(3)-ln(2))