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Popular >

2^x=4^{2x-1}

Solution

2^{x} = 4^{2 x - 1}

Solution

x = \frac{2}{3}

+1

Decimal Notation

x = 0.66666 \dots

Solution steps

2^{x} = 4^{2 x - 1}

Apply exponent rules

x = 2 (2 x - 1)

Solve

x = 2 (2 x - 1) : x = \frac{2}{3}

x = \frac{2}{3}

Popular Examples

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y, e^{y} - p^{3} - p = 0

729*(2^{n-5})^n-64*(3^n)^{n-5}=0

729 \cdot (2^{n - 5})^{n} - 64 \cdot (3^{n})^{n - 5} = 0

4^{1/((log_{2)(x))}}=2

4^{\frac{1}{( l o g _{2} ( x ) )}} = 2

8^x=16^{-1}*sqrt(32^x)

8^{x} = 1 6^{- 1} \cdot 3 2^{x}

1/64 =(1/2)^{n-1}

\frac{1}{64} = (\frac{1}{2})^{n - 1}

Frequently Asked Questions (FAQ)

What is the answer to 2^x=4^{2x-1} ?
The answer to 2^x=4^{2x-1} is x= 2/3
Solve for x: 2^x=4^{2x-1}
The solution is x= 2/3