What is the answer to 4^{1/((log_{2)(x))}}=2 ?

The answer to 4^{1/((log_{2)(x))}}=2 is x=4

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4^{1/((log_{2)(x))}}=2

4^{\frac{1}{( l o g _{2} ( x ) )}} = 2

x = 4

Solution steps

4^{\frac{1}{( l o g _{2} ( x ) )}} = 2

Apply exponent rules

\frac{2}{lo g _{2} ( x )} = 1

Solve

\frac{2}{lo g _{2} ( x )} = 1 : x = 4

x = 4

8^{x} = 1 6^{- 1} \cdot 3 2^{x}

\frac{1}{64} = (\frac{1}{2})^{n - 1}

3^{2 x + 1} = 5^{2 x + 1}

1 0^{x} = - 2

6^{5 x} = 27

What is the answer to 4^{1/((log_{2)(x))}}=2 ?
The answer to 4^{1/((log_{2)(x))}}=2 is x=4
Solve for x: 4^{1/((log_{2)(x))}}=2
The solution is x=4