What is the answer to 2^{3+x}=5^{x-4} ?

The answer to 2^{3+x}=5^{x-4} is x=(ln(5000))/(ln(5)-ln(2))

Solve for x: 2^{3+x}=5^{x-4}

The solution is x=(ln(5000))/(ln(5)-ln(2))

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2^{3 + x} = 5^{x - 4}

x = \frac{ln ( 5000 )}{ln ( 5 ) - ln ( 2 )}

Decimal Notation

x = 9.29529 \dots

Solution steps

2^{3 + x} = 5^{x - 4}

Apply exponent rules

(3 + x) ln (2) = (x - 4) ln (5)

Solve

(3 + x) ln (2) = (x - 4) ln (5) : x = \frac{ln ( 5000 )}{ln ( 5 ) - ln ( 2 )}

x = \frac{ln ( 5000 )}{ln ( 5 ) - ln ( 2 )}

2 \cdot 5^{x} + 2 5^{x} = 3

4^{x} + 4^{x + 1} = 80

14 4^{3 x + 5} = (\frac{1}{2})^{6 x}

2^{x} + 1 + 2^{x} + 2^{x} - 1 = 28

(a - 1)^{2} = a^{x} - 1

What is the answer to 2^{3+x}=5^{x-4} ?
The answer to 2^{3+x}=5^{x-4} is x=(ln(5000))/(ln(5)-ln(2))
Solve for x: 2^{3+x}=5^{x-4}
The solution is x=(ln(5000))/(ln(5)-ln(2))