What is the answer to 2^x+1+2^x+2^x-1=28 ?

The answer to 2^x+1+2^x+2^x-1=28 is x=(ln(28/3))/(ln(2))

Solve for x: 2^x+1+2^x+2^x-1=28

The solution is x=(ln(28/3))/(ln(2))

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2^{x} + 1 + 2^{x} + 2^{x} - 1 = 28

x = \frac{ln ( \frac{28}{3} )}{ln ( 2 )}

Decimal Notation

x = 3.22239 \dots

Solution steps

2^{x} + 1 + 2^{x} + 2^{x} - 1 = 28

Group like terms

2^{x} + 2^{x} + 2^{x} + 1 - 1 = 28

Add similar elements:

2^{x} + 2^{x} + 2^{x} = 3 \cdot 2^{x}

3 \cdot 2^{x} + 1 - 1 = 28

1 - 1 = 0

3 \cdot 2^{x} = 28

Divide both sides by

3

2^{x} = \frac{28}{3}

Apply exponent rules

x ln (2) = ln (\frac{28}{3})

Solve

x ln (2) = ln (\frac{28}{3}) : x = \frac{ln ( \frac{28}{3} )}{ln ( 2 )}

x = \frac{ln ( \frac{28}{3} )}{ln ( 2 )}

(a - 1)^{2} = a^{x} - 1

6^{x} = 34

8^{x} - 1 = 16

42 e^{\frac{x}{4}} = 32

8^{7 x + 9} = 2^{3 x + 6}

What is the answer to 2^x+1+2^x+2^x-1=28 ?
The answer to 2^x+1+2^x+2^x-1=28 is x=(ln(28/3))/(ln(2))
Solve for x: 2^x+1+2^x+2^x-1=28
The solution is x=(ln(28/3))/(ln(2))