What is the answer to (3^{42}*9^{12})^{1/3}=3^k ?

The answer to (3^{42}*9^{12})^{1/3}=3^k is k=22

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(3^{42}*9^{12})^{1/3}=3^k

(3^{42} \cdot 9^{12})^{\frac{1}{3}} = 3^{k}

k = 22

Solution steps

(3^{42} \cdot 9^{12})^{\frac{1}{3}} = 3^{k}

Apply exponent rules

22 = k

Switch sides

k = 22

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5^{x} (5^{x} - 4) + 3 = 0

(- 15)^{x} = 1

What is the answer to (3^{42}*9^{12})^{1/3}=3^k ?
The answer to (3^{42}*9^{12})^{1/3}=3^k is k=22
Solve for k: (3^{42}*9^{12})^{1/3}=3^k
The solution is k=22