What is the answer to 5^x(5^x-4)+3=0 ?

The answer to 5^x(5^x-4)+3=0 is x=(ln(3))/(ln(5)),x=0

Solve for x: 5^x(5^x-4)+3=0

The solution is x=(ln(3))/(ln(5)),x=0

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5^{x} (5^{x} - 4) + 3 = 0

x = \frac{ln ( 3 )}{ln ( 5 )}, x = 0

Decimal Notation

x = 0.68260 \dots, x = 0

Solution steps

5^{x} (5^{x} - 4) + 3 = 0

Subtract

3

from both sides

5^{x} (5^{x} - 4) + 3 - 3 = 0 - 3

Simplify

5^{x} (5^{x} - 4) = - 3

Rewrite the equation with

5^{x} = u

u (u - 4) = - 3

Solve

u (u - 4) = - 3 : u = 3, u = 1

u = 3, u = 1

Substitute back

u = 5^{x},

solve for

x

Solve

5^{x} = 3 : x = \frac{ln ( 3 )}{ln ( 5 )}

Solve

5^{x} = 1 : x = 0

x = \frac{ln ( 3 )}{ln ( 5 )}, x = 0

(- 15)^{x} = 1

1 0^{2 x - 3} = (0.1)^{2}

x, 4^{x + y} = 3^{x^{2} + y^{2}}

1 0^{x} = 25

2^{l o g_{2} (x^{2})} - 3 x - 4 = 0

What is the answer to 5^x(5^x-4)+3=0 ?
The answer to 5^x(5^x-4)+3=0 is x=(ln(3))/(ln(5)),x=0
Solve for x: 5^x(5^x-4)+3=0
The solution is x=(ln(3))/(ln(5)),x=0