What is the answer to 2^{log_{2}(x^2)}-3x-4=0 ?

The answer to 2^{log_{2}(x^2)}-3x-4=0 is x=-1,x=4

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2^{log_{2}(x^2)}-3x-4=0

2^{l o g_{2} (x^{2})} - 3 x - 4 = 0

x = - 1, x = 4

Solution steps

2^{l o g_{2} (x^{2})} - 3 x - 4 = 0

Factor

2^{l o g_{2} (x^{2})} - 3 x - 4 : (x + 1) (x - 4)

(x + 1) (x - 4) = 0

Solve

(x + 1) (x - 4) = 0 : x = - 1, x = 4

x = - 1, x = 4

2^{x + 2} + 2^{x - 1} = 9

lo g_{10} (9^{x}) = 1.5

1 0^{x} = 33

3^{x} + 2 x - 5 = 0

2^{5 x + 2} = 8^{9}

What is the answer to 2^{log_{2}(x^2)}-3x-4=0 ?
The answer to 2^{log_{2}(x^2)}-3x-4=0 is x=-1,x=4
Solve for x: 2^{log_{2}(x^2)}-3x-4=0
The solution is x=-1,x=4