What is the answer to 10^x=33 ?

The answer to 10^x=33 is x=(ln(33))/(ln(10))

The solution is x=(ln(33))/(ln(10))

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10^x=33

1 0^{x} = 33

x = \frac{ln ( 33 )}{ln ( 10 )}

Decimal Notation

x = 1.51851 \dots

Solution steps

1 0^{x} = 33

Apply exponent rules

x ln (10) = ln (33)

Solve

x ln (10) = ln (33) : x = \frac{ln ( 33 )}{ln ( 10 )}

x = \frac{ln ( 33 )}{ln ( 10 )}

3^{x} + 2 x - 5 = 0

2^{5 x + 2} = 8^{9}

(\frac{( 2 ^{1 - 2 x} )}{( 2 ^{x + 3} )})^{3} = 4

y, \frac{( 2 ^{y} - 1 )}{( 2 ^{y} + 1 )} = x

3^{x} = 171