What is the answer to 5^{2x-1}=25^{x-1} ?

The answer to 5^{2x-1}=25^{x-1} is No Solution for x\in\mathbb{R}

Solve for x: 5^{2x-1}=25^{x-1}

The solution is No Solution for x\in\mathbb{R}

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5^{2 x - 1} = 2 5^{x - 1}

No Solution for x \in R

Solution steps

5^{2 x - 1} = 2 5^{x - 1}

Apply exponent rules

2 x - 1 = 2 (x - 1)

Solve

2 x - 1 = 2 (x - 1) :

No Solution

No Solution for x \in R

(2. 1^{- 8})^{3} = 80. 1^{a}

9^{3 x} = (\frac{1}{3})^{2 x - 1}

2^{x} = \frac{2}{3}

8^{9 x + 1} = 2^{x^{2} + 29 x}

x, y = {e^{- 2 x}}

What is the answer to 5^{2x-1}=25^{x-1} ?
The answer to 5^{2x-1}=25^{x-1} is No Solution for x\in\mathbb{R}
Solve for x: 5^{2x-1}=25^{x-1}
The solution is No Solution for x\in\mathbb{R}