What is the answer to 8^{9x+1}=2^{x^2+29x} ?

The answer to 8^{9x+1}=2^{x^2+29x} is x=1,x=-3

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8^{9x+1}=2^{x^2+29x}

8^{9 x + 1} = 2^{x^{2} + 29 x}

x = 1, x = - 3

Solution steps

8^{9 x + 1} = 2^{x^{2} + 29 x}

Apply exponent rules

3 (9 x + 1) = x^{2} + 29 x

Solve

3 (9 x + 1) = x^{2} + 29 x : x = 1, x = - 3

x = 1, x = - 3

x, y = {e^{- 2 x}}

p, \frac{2 ^{x - 2} \cdot 1}{2} = p (x)^{x - 3}

3 = 0.5 \cdot 1.0 5^{x}

5^{x^{2} + 3 x} = 1

4^{x - 5} = 9

What is the answer to 8^{9x+1}=2^{x^2+29x} ?
The answer to 8^{9x+1}=2^{x^2+29x} is x=1,x=-3
Solve for x: 8^{9x+1}=2^{x^2+29x}
The solution is x=1,x=-3