What is the answer to (7/5)^{x-1}=(5/7)^{x-3} ?

The answer to (7/5)^{x-1}=(5/7)^{x-3} is x=2

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(7/5)^{x-1}=(5/7)^{x-3}

(\frac{7}{5})^{x - 1} = (\frac{5}{7})^{x - 3}

x = 2

Solution steps

(\frac{7}{5})^{x - 1} = (\frac{5}{7})^{x - 3}

Apply exponent rules

x - 1 = - (x - 3)

Solve

x - 1 = - (x - 3) : x = 2

x = 2

y, x^{4} - 2 x^{y} - 1 = 0

10 t e^{- t} = 0

(\frac{21}{20})^{n} = \frac{27783}{24000}

3^{- 2} \cdot 0. 3^{4} \cdot 0. 3^{n} = 3

\frac{2 ^{t}}{3.8} = 20

What is the answer to (7/5)^{x-1}=(5/7)^{x-3} ?
The answer to (7/5)^{x-1}=(5/7)^{x-3} is x=2
Solve for x: (7/5)^{x-1}=(5/7)^{x-3}
The solution is x=2