What is the answer to 2*3^{x+1}+3^{x+3}=33 ?

The answer to 2*3^{x+1}+3^{x+3}=33 is x=0

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2*3^{x+1}+3^{x+3}=33

2 \cdot 3^{x + 1} + 3^{x + 3} = 33

x = 0

Solution steps

2 \cdot 3^{x + 1} + 3^{x + 3} = 33

Factor

2 \cdot 3^{x + 1} + 3^{x + 3} : 11 \cdot 3^{x + 1}

11 \cdot 3^{x + 1} = 33

Divide both sides by

11

3^{x + 1} = 3

Apply exponent rules

x + 1 = 1

Solve

x + 1 = 1 : x = 0

x = 0

x, 2^{x + 1} - 1 = 7^{y}

2^{4 x + 3} = 8^{x - 5}

5^{2 x + 1} = 3^{4 x - 1}

2 e^{0.5} x = e^{x}

a, x^{2} \cdot y^{3} = x^{a} \cdot y^{b}

What is the answer to 2*3^{x+1}+3^{x+3}=33 ?
The answer to 2*3^{x+1}+3^{x+3}=33 is x=0
Solve for x: 2*3^{x+1}+3^{x+3}=33
The solution is x=0