What is the answer to 5^{2x+1}=3^{4x-1} ?

The answer to 5^{2x+1}=3^{4x-1} is x=-(ln(15))/(2(ln(5)-2ln(3)))

Solve for x: 5^{2x+1}=3^{4x-1}

The solution is x=-(ln(15))/(2(ln(5)-2ln(3)))

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5^{2 x + 1} = 3^{4 x - 1}

x = - \frac{ln ( 15 )}{2 ( ln ( 5 ) - 2 ln ( 3 ) )}

Decimal Notation

x = 2.30359 \dots

Solution steps

5^{2 x + 1} = 3^{4 x - 1}

Apply exponent rules

(2 x + 1) ln (5) = (4 x - 1) ln (3)

Solve

(2 x + 1) ln (5) = (4 x - 1) ln (3) : x = - \frac{ln ( 15 )}{2 ( ln ( 5 ) - 2 ln ( 3 ) )}

x = - \frac{ln ( 15 )}{2 ( ln ( 5 ) - 2 ln ( 3 ) )}

2 e^{0.5} x = e^{x}

a, x^{2} \cdot y^{3} = x^{a} \cdot y^{b}

2^{x + 2} = 5

x, 2^{x} - 2^{y} = 256

5^{7 x - 4} = (\frac{1}{625})^{x + 6}

What is the answer to 5^{2x+1}=3^{4x-1} ?
The answer to 5^{2x+1}=3^{4x-1} is x=-(ln(15))/(2(ln(5)-2ln(3)))
Solve for x: 5^{2x+1}=3^{4x-1}
The solution is x=-(ln(15))/(2(ln(5)-2ln(3)))