What is the answer to 2^{x+2}=5 ?

The answer to 2^{x+2}=5 is x=(ln(5))/(ln(2))-2

Solve for x: 2^{x+2}=5

The solution is x=(ln(5))/(ln(2))-2

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2^{x + 2} = 5

x = \frac{ln ( 5 )}{ln ( 2 )} - 2

Decimal Notation

x = 0.32192 \dots

Solution steps

2^{x + 2} = 5

Apply exponent rules

(x + 2) ln (2) = ln (5)

Solve

(x + 2) ln (2) = ln (5) : x = \frac{ln ( 5 )}{ln ( 2 )} - 2

x = \frac{ln ( 5 )}{ln ( 2 )} - 2

x, 2^{x} - 2^{y} = 256

5^{7 x - 4} = (\frac{1}{625})^{x + 6}

5^{x} = - 3

2^{x - 1} = (2)^{x}

(16)^{3 n} = 8^{5}

What is the answer to 2^{x+2}=5 ?
The answer to 2^{x+2}=5 is x=(ln(5))/(ln(2))-2
Solve for x: 2^{x+2}=5
The solution is x=(ln(5))/(ln(2))-2