What is the answer to 4^x=81 ?

The answer to 4^x=81 is x=(2ln(3))/(ln(2))

The solution is x=(2ln(3))/(ln(2))

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4^x=81

4^{x} = 81

x = \frac{2 ln ( 3 )}{ln ( 2 )}

Decimal Notation

x = 3.16992 \dots

Solution steps

4^{x} = 81

Apply exponent rules

x ln (4) = ln (81)

Solve

x ln (4) = ln (81) : x = \frac{2 ln ( 3 )}{ln ( 2 )}

x = \frac{2 ln ( 3 )}{ln ( 2 )}

2^{x - 2} = 4^{2021}

3^{x} + 3^{x + 1} = 36

3^{x} - 0.5 = 0

((\frac{1}{16})^{- 2})^{3} = 4^{- x}

2^{x} = x^{4}