What is the answer to 3^x-0.5=0 ?

The answer to 3^x-0.5=0 is x=(ln(0.5))/(ln(3))

Solve for x: 3^x-0.5=0

The solution is x=(ln(0.5))/(ln(3))

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3^{x} - 0.5 = 0

x = \frac{ln ( 0.5 )}{ln ( 3 )}

Decimal Notation

x = - 0.63092 \dots

Solution steps

3^{x} - 0.5 = 0

Add

0.5

to both sides

3^{x} - 0.5 + 0.5 = 0 + 0.5

Simplify

3^{x} = 0.5

Apply exponent rules

x ln (3) = ln (0.5)

Solve

x ln (3) = ln (0.5) : x = \frac{ln ( 0.5 )}{ln ( 3 )}

x = \frac{ln ( 0.5 )}{ln ( 3 )}

((\frac{1}{16})^{- 2})^{3} = 4^{- x}

2^{x} = x^{4}

1.2 5^{x} = 0.512

(- 3)^{x - 1} = 729

(\frac{1}{2 ^{x - 4}}) - (\frac{1}{2 ^{x - 2}}) = 3

What is the answer to 3^x-0.5=0 ?
The answer to 3^x-0.5=0 is x=(ln(0.5))/(ln(3))
Solve for x: 3^x-0.5=0
The solution is x=(ln(0.5))/(ln(3))