What are the solutions to the equation 3x^2-12x=10 ?

The solutions to the equation 3x^2-12x=10 are x=(6+sqrt(66))/3 ,x=(6-sqrt(66))/3

Find the zeros of 3x^2-12x=10

The zeros of 3x^2-12x=10 are x=(6+sqrt(66))/3 ,x=(6-sqrt(66))/3

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3 x^{2} - 12 x = 10

x = \frac{6 + 66}{3}, x = \frac{6 - 66}{3}

Solution steps

3 x^{2} - 12 x = 10

Move

10

to the left side

3 x^{2} - 12 x - 10 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 12 ) \pm ( - 12 ) ^{2} - 4 \cdot 3 ( - 10 )}{2 \cdot 3}

(- 12)^{2} - 4 \cdot 3 (- 10) = 266

x_{1, 2} = \frac{- ( - 12 ) \pm 2 66}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- ( - 12 ) + 2 66}{2 \cdot 3}, x_{2} = \frac{- ( - 12 ) - 2 66}{2 \cdot 3}

x = \frac{- ( - 12 ) + 2 66}{2 \cdot 3} : \frac{6 + 66}{3}

x = \frac{- ( - 12 ) - 2 66}{2 \cdot 3} : \frac{6 - 66}{3}

The solutions to the quadratic equation are:

x = \frac{6 + 66}{3}, x = \frac{6 - 66}{3}

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3 x^{2} - 42 x - 5 = 0

(x + 5) (x - 5)

(x - 2 + 3 i) (x - 2 - 3 i)

What are the solutions to the equation 3x^2-12x=10 ?
The solutions to the equation 3x^2-12x=10 are x=(6+sqrt(66))/3 ,x=(6-sqrt(66))/3
Find the zeros of 3x^2-12x=10
The zeros of 3x^2-12x=10 are x=(6+sqrt(66))/3 ,x=(6-sqrt(66))/3