What is the answer to 5^{-x}=2 ?

The answer to 5^{-x}=2 is x=-(ln(2))/(ln(5))

Solve for x: 5^{-x}=2

The solution is x=-(ln(2))/(ln(5))

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5^{- x} = 2

x = - \frac{ln ( 2 )}{ln ( 5 )}

Decimal Notation

x = - 0.43067 \dots

Solution steps

5^{- x} = 2

Apply exponent rules

- x ln (5) = ln (2)

Solve

- x ln (5) = ln (2) : x = - \frac{ln ( 2 )}{ln ( 5 )}

x = - \frac{ln ( 2 )}{ln ( 5 )}

2^{x - 3} = 6^{2 x - 1}

1 6^{2 x + 10} = 1 6^{2 x - 1}

9^{2 - x} = 3

1 = 2^{n}

5^{x} \cdot lo g_{10} (1000) = 27