What is the answer to sqrt(16^{2x+10)}=16^{2x-1} ?

The answer to sqrt(16^{2x+10)}=16^{2x-1} is x=6

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sqrt(16^{2x+10)}=16^{2x-1}

1 6^{2 x + 10} = 1 6^{2 x - 1}

x = 6

Solution steps

1 6^{2 x + 10} = 1 6^{2 x - 1}

Apply exponent rules

x + 5 = 2 x - 1

Solve

x + 5 = 2 x - 1 : x = 6

x = 6

9^{2 - x} = 3

1 = 2^{n}

5^{x} \cdot lo g_{10} (1000) = 27

2^{x + 1} = 4^{2 x}

4^{x} = \frac{1}{32}

What is the answer to sqrt(16^{2x+10)}=16^{2x-1} ?
The answer to sqrt(16^{2x+10)}=16^{2x-1} is x=6
Solve for x: sqrt(16^{2x+10)}=16^{2x-1}
The solution is x=6