What is the answer to [4^{x+1}]-(4^x)=48 ?

The answer to [4^{x+1}]-(4^x)=48 is x=2

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[4^{x+1}]-(4^x)=48

[4^{x + 1}] - (4^{x}) = 48

x = 2

Solution steps

[4^{x + 1}] - (4^{x}) = 48

Factor

(4^{x + 1}) - 4^{x} : 3 \cdot 4^{x}

3 \cdot 4^{x} = 48

Divide both sides by

3

4^{x} = 16

Apply exponent rules

x = 2

e^{- 2 x} - 2 e^{- x} = 0

e^{x} = - 6

2^{n - 3} \cdot 1 4^{4 n - 5} = \frac{1}{56}

3^{x - 1} = (\frac{1}{2})^{x + 3}

\frac{- 32}{243} = (\frac{- 2}{3})^{2 n + 1}

What is the answer to [4^{x+1}]-(4^x)=48 ?
The answer to [4^{x+1}]-(4^x)=48 is x=2
Solve for x: [4^{x+1}]-(4^x)=48
The solution is x=2