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Popular >

2^x=n

Solution

2^{x} = n

Solution

x = \frac{ln ( n )}{ln ( 2 )}

Solution steps

2^{x} = n

Apply exponent rules

x ln (2) = ln (n)

Solve

x ln (2) = ln (n) : x = \frac{ln ( n )}{ln ( 2 )}

x = \frac{ln ( n )}{ln ( 2 )}

Popular Examples

solvefor x,8^{2x}-4(8^x)=3g solve for

x, 8^{2 x} - 4 (8^{x}) = 3 g

9^{x+1}+1=10(3^x)

9^{x + 1} + 1 = 10 (3^{x})

x^{2x-1}=x^{2x-5}

x^{2 x - 1} = x^{2 x - 5}

(8^{-x})(2^{x^2-2x})=1

(8^{- x}) (2^{x^{2} - 2 x}) = 1

3^{1-(2*x)}=4^x

3^{1 - (2 \cdot x)} = 4^{x}

Frequently Asked Questions (FAQ)

What is the answer to 2^x=n ?
The answer to 2^x=n is x=(ln(n))/(ln(2))