What is the answer to (8^{-x})(2^{x^2-2x})=1 ?

The answer to (8^{-x})(2^{x^2-2x})=1 is x=0,x=5

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(8^{-x})(2^{x^2-2x})=1

(8^{- x}) (2^{x^{2} - 2 x}) = 1

x = 0, x = 5

Solution steps

(8^{- x}) (2^{x^{2} - 2 x}) = 1

Apply exponent rules

(3 (- x) + x^{2} - 2 x) ln (2) = ln (1)

Solve

(3 (- x) + x^{2} - 2 x) ln (2) = ln (1) : x = 0, x = 5

x = 0, x = 5

3^{1 - (2 \cdot x)} = 4^{x}

e^{2} x - 3 e^{x} + 2 = 0

e^{z} = 2

e^{z} = 1

2^{- 2 x - 5} = 6^{4 - 4 x}

What is the answer to (8^{-x})(2^{x^2-2x})=1 ?
The answer to (8^{-x})(2^{x^2-2x})=1 is x=0,x=5
Solve for x: (8^{-x})(2^{x^2-2x})=1
The solution is x=0,x=5