What is the answer to 2^{-2x-5}=6^{4-4x} ?

The answer to 2^{-2x-5}=6^{4-4x} is x=(4ln(6)+5ln(2))/(2ln(18))

Solve for x: 2^{-2x-5}=6^{4-4x}

The solution is x=(4ln(6)+5ln(2))/(2ln(18))

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

2^{- 2 x - 5} = 6^{4 - 4 x}

x = \frac{4 ln ( 6 ) + 5 ln ( 2 )}{2 ln ( 18 )}

Decimal Notation

x = 1.83934 \dots

Solution steps

2^{- 2 x - 5} = 6^{4 - 4 x}

Apply exponent rules

(- 2 x - 5) ln (2) = (4 - 4 x) ln (6)

Solve

(- 2 x - 5) ln (2) = (4 - 4 x) ln (6) : x = \frac{4 ln ( 6 ) + 5 ln ( 2 )}{2 ln ( 18 )}

x = \frac{4 ln ( 6 ) + 5 ln ( 2 )}{2 ln ( 18 )}

n^{n} = 6

5^{x} - 2 + 5^{x} - 1 = \frac{30}{5}

4^{x} + 4^{2 x} = 272

3 - 2^{x} = - 5

\frac{a ^{x} + 1}{a ^{x}} = n

What is the answer to 2^{-2x-5}=6^{4-4x} ?
The answer to 2^{-2x-5}=6^{4-4x} is x=(4ln(6)+5ln(2))/(2ln(18))
Solve for x: 2^{-2x-5}=6^{4-4x}
The solution is x=(4ln(6)+5ln(2))/(2ln(18))