What is the answer to 5^x-2+5^x-1= 30/5 ?

The answer to 5^x-2+5^x-1= 30/5 is x=(ln(9/2))/(ln(5))

Solve for x: 5^x-2+5^x-1= 30/5

The solution is x=(ln(9/2))/(ln(5))

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5^{x} - 2 + 5^{x} - 1 = \frac{30}{5}

x = \frac{ln ( \frac{9}{2} )}{ln ( 5 )}

Decimal Notation

x = 0.93453 \dots

Solution steps

5^{x} - 2 + 5^{x} - 1 = \frac{30}{5}

Group like terms

5^{x} + 5^{x} - 2 - 1 = \frac{30}{5}

Add similar elements:

5^{x} + 5^{x} = 2 \cdot 5^{x}

2 \cdot 5^{x} - 2 - 1 = \frac{30}{5}

Subtract the numbers:

- 2 - 1 = - 3

2 \cdot 5^{x} - 3 = \frac{30}{5}

Divide the numbers:

\frac{30}{5} = 6

2 \cdot 5^{x} - 3 = 6

Move

3

to the right side

2 \cdot 5^{x} = 9

Divide both sides by

2

5^{x} = \frac{9}{2}

Apply exponent rules

x ln (5) = ln (\frac{9}{2})

Solve

x ln (5) = ln (\frac{9}{2}) : x = \frac{ln ( \frac{9}{2} )}{ln ( 5 )}

x = \frac{ln ( \frac{9}{2} )}{ln ( 5 )}

4^{x} + 4^{2 x} = 272

3 - 2^{x} = - 5

\frac{a ^{x} + 1}{a ^{x}} = n

2^{\frac{2}{( l o g _{5} ( x ) )}} = \frac{1}{16}

x, (d^{3} + 2 d^{2} - d - 2) = e^{x}

What is the answer to 5^x-2+5^x-1= 30/5 ?
The answer to 5^x-2+5^x-1= 30/5 is x=(ln(9/2))/(ln(5))
Solve for x: 5^x-2+5^x-1= 30/5
The solution is x=(ln(9/2))/(ln(5))