What is the answer to 2^{2/((log_{5)(x))}}= 1/16 ?

The answer to 2^{2/((log_{5)(x))}}= 1/16 is x= 1/(5^{1/2)}

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

2^{2/((log_{5)(x))}}= 1/16

2^{\frac{2}{( l o g _{5} ( x ) )}} = \frac{1}{16}

x = \frac{1}{5 ^{\frac{1}{2}}}

Decimal Notation

x = 0.4472135955

Solution steps

2^{\frac{2}{( l o g _{5} ( x ) )}} = \frac{1}{16}

Multiply both sides by

16

2^{\frac{2}{l o g _{5} ( x )}} \cdot 16 = \frac{1}{16} \cdot 16

Simplify

2^{\frac{2}{l o g _{5} ( x )}} \cdot 16 = 1

Divide both sides by

16

2^{\frac{2}{l o g _{5} ( x )}} = \frac{1}{16}

Apply exponent rules

\frac{2}{lo g _{5} ( x )} = - 4

Solve

\frac{2}{lo g _{5} ( x )} = - 4 : x = \frac{1}{5 ^{\frac{1}{2}}}

x = \frac{1}{5 ^{\frac{1}{2}}}

Verify Solutions:

x = \frac{1}{5 ^{\frac{1}{2}}}

True

The solution is

x = \frac{1}{5 ^{\frac{1}{2}}}

x, (d^{3} + 2 d^{2} - d - 2) = e^{x}

\frac{( 3 2 ^{x - 4} )}{( 4 ^{x - 4} )} = 8^{3 x + 2}

3. 2^{x} + 2^{- 6} = 48

m, 2^{m} 0. 3^{n} 0.72 = 1

x, \frac{1}{a ^{x}} = e^{- y}

What is the answer to 2^{2/((log_{5)(x))}}= 1/16 ?
The answer to 2^{2/((log_{5)(x))}}= 1/16 is x= 1/(5^{1/2)}
Solve for x: 2^{2/((log_{5)(x))}}= 1/16
The solution is x= 1/(5^{1/2)}