What is the answer to 64^{2x-5}=32^{x-4} ?

The answer to 64^{2x-5}=32^{x-4} is x= 10/7

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64^{2x-5}=32^{x-4}

6 4^{2 x - 5} = 3 2^{x - 4}

x = \frac{10}{7}

Decimal Notation

x = 1.42857 \dots

Solution steps

6 4^{2 x - 5} = 3 2^{x - 4}

Apply exponent rules

6 (2 x - 5) = 5 (x - 4)

Solve

6 (2 x - 5) = 5 (x - 4) : x = \frac{10}{7}

x = \frac{10}{7}

n, 2 = t + t^{n}

\frac{( 2 ^{x} \cdot 3 ^{x} )}{( 1 2 ^{x} )} = \frac{1}{8}

32 = 8^{x}

4^{3 x - 1} = 5^{x + 1}

1 0^{x} = 3 - 2 x

What is the answer to 64^{2x-5}=32^{x-4} ?
The answer to 64^{2x-5}=32^{x-4} is x= 10/7
Solve for x: 64^{2x-5}=32^{x-4}
The solution is x= 10/7