What is the answer to solvefor x,d^2+d-2=e^x ?

The answer to solvefor x,d^2+d-2=e^x is x=ln(d^2+d-2)

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solvefor x,d^2+d-2=e^x

solve for

x, d^{2} + d - 2 = e^{x}

x = ln (d^{2} + d - 2)

Solution steps

d^{2} + d - 2 = e^{x}

Apply exponent rules

ln (d^{2} + d - 2) = x

Switch sides

x = ln (d^{2} + d - 2)

3^{40} + 3^{40} + 3^{x} = 3^{41}

5^{x + 1} = 5^{x} + 100

9 e^{\frac{- x}{2}} + 12 e^{\frac{- x}{6}} = 0

8^{3} x - 1 = 7^{x} + 2

2^{2 x + 1} - 33 (2^{x - 1}) + 4 = 0

What is the answer to solvefor x,d^2+d-2=e^x ?
The answer to solvefor x,d^2+d-2=e^x is x=ln(d^2+d-2)