What is the answer to (1/9)^{6x+1}=9^{7-x} ?

The answer to (1/9)^{6x+1}=9^{7-x} is x=-8/5

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(1/9)^{6x+1}=9^{7-x}

(\frac{1}{9})^{6 x + 1} = 9^{7 - x}

x = - \frac{8}{5}

Decimal Notation

x = - 1.6

Solution steps

(\frac{1}{9})^{6 x + 1} = 9^{7 - x}

Apply exponent rules

- (6 x + 1) = 7 - x

Solve

- (6 x + 1) = 7 - x : x = - \frac{8}{5}

x = - \frac{8}{5}

x, y^{x} - y^{y} = - 26

x^{(l o g_{10} (x)) + 2} = 1 0^{(l o g_{10} (x)) + 2}

(- 3)^{x} = 87

x, (2^{2})^{x} - (3^{2})^{y} = 55

x, ((3^{x})^{5})^{y} = 225

What is the answer to (1/9)^{6x+1}=9^{7-x} ?
The answer to (1/9)^{6x+1}=9^{7-x} is x=-8/5
Solve for x: (1/9)^{6x+1}=9^{7-x}
The solution is x=-8/5