What is the answer to 2^{2x-3}=4^{x^2-3x-1} ?

The answer to 2^{2x-3}=4^{x^2-3x-1} is x=(4+sqrt(14))/2 ,x=(4-sqrt(14))/2

Solve for x: 2^{2x-3}=4^{x^2-3x-1}

The solution is x=(4+sqrt(14))/2 ,x=(4-sqrt(14))/2

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2^{2 x - 3} = 4^{x^{2} - 3 x - 1}

x = \frac{4 + 14}{2}, x = \frac{4 - 14}{2}

Decimal Notation

x = 3.87082 \dots, x = 0.12917 \dots

Solution steps

2^{2 x - 3} = 4^{x^{2} - 3 x - 1}

Apply exponent rules

2 x - 3 = 2 (x^{2} - 3 x - 1)

Solve

2 x - 3 = 2 (x^{2} - 3 x - 1) : x = \frac{4 + 14}{2}, x = \frac{4 - 14}{2}

x = \frac{4 + 14}{2}, x = \frac{4 - 14}{2}

2^{2 x + 1} - 15 (2^{x}) - 8 = 0

x, (2007)^{x} + (2007)^{y} = 1

n = \frac{( 2 ^{n + 4} - 2 ^{n + 3} )}{( 2 ^{n + 4} )}

\frac{8 1 ^{2}}{( 72 9 ^{1} ) ^{- x}} = (9^{2})^{x}

2^{x - 4} = 4. 2^{x - 6}

What is the answer to 2^{2x-3}=4^{x^2-3x-1} ?
The answer to 2^{2x-3}=4^{x^2-3x-1} is x=(4+sqrt(14))/2 ,x=(4-sqrt(14))/2
Solve for x: 2^{2x-3}=4^{x^2-3x-1}
The solution is x=(4+sqrt(14))/2 ,x=(4-sqrt(14))/2