What is the answer to 2^x=40 ?

The answer to 2^x=40 is x=(ln(40))/(ln(2))

The solution is x=(ln(40))/(ln(2))

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2^x=40

2^{x} = 40

x = \frac{ln ( 40 )}{ln ( 2 )}

Decimal Notation

x = 5.32192 \dots

Solution steps

2^{x} = 40

Apply exponent rules

x ln (2) = ln (40)

Solve

x ln (2) = ln (40) : x = \frac{ln ( 40 )}{ln ( 2 )}

x = \frac{ln ( 40 )}{ln ( 2 )}

c, p (b^{c}) = 0.7

2^{x + 3} + 2^{x + 1} = 80

- 5^{x + 1} + 8 \cdot 5^{x} = 15 \cdot 5^{- 3}

2^{x + 1} = 3^{x - 4}

5^{x} = 0.2