What is the answer to 2^x= 4/9 ?

The answer to 2^x= 4/9 is x=(ln(4/9))/(ln(2))

Solve for x: 2^x= 4/9

The solution is x=(ln(4/9))/(ln(2))

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2^{x} = \frac{4}{9}

x = \frac{ln ( \frac{4}{9} )}{ln ( 2 )}

Decimal Notation

x = - 1.16992 \dots

Solution steps

2^{x} = \frac{4}{9}

Apply exponent rules

x ln (2) = ln (\frac{4}{9})

Solve

x ln (2) = ln (\frac{4}{9}) : x = \frac{ln ( \frac{4}{9} )}{ln ( 2 )}

x = \frac{ln ( \frac{4}{9} )}{ln ( 2 )}

2^{x} \cdot 4^{x} = 8^{\frac{1}{3}}

3^{x} + 1 = 4

3 \cdot 2^{x} = 15

(\frac{3}{4})^{1 - 3 x} = \frac{210}{27}

x, 7 7^{x} + 8 8^{y} = 6776