What is the answer to 27^{x-1}=(1/9)^x ?

The answer to 27^{x-1}=(1/9)^x is x= 3/5

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27^{x-1}=(1/9)^x

2 7^{x - 1} = (\frac{1}{9})^{x}

x = \frac{3}{5}

Decimal Notation

x = 0.6

Solution steps

2 7^{x - 1} = (\frac{1}{9})^{x}

Apply exponent rules

3 (x - 1) = - 2 x

Solve

3 (x - 1) = - 2 x : x = \frac{3}{5}

x = \frac{3}{5}

x, 2 u + 3 v = e^{x} (cos (y) - sin (y))

e^{y} = 0

2^{x + 3} + 2^{x} = 72

2^{x + 3} = 4^{x - 1}

2^{x + 1} + 2^{x} - 2^{x} - 2 = 88

What is the answer to 27^{x-1}=(1/9)^x ?
The answer to 27^{x-1}=(1/9)^x is x= 3/5
Solve for x: 27^{x-1}=(1/9)^x
The solution is x= 3/5