What is the answer to (2x^2-1)^{5x+2}=(2x^2-1)^{x^2+6} ?

The answer to (2x^2-1)^{5x+2}=(2x^2-1)^{x^2+6} is x=1,x=-1,x=4

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(2x^2-1)^{5x+2}=(2x^2-1)^{x^2+6}

(2 x^{2} - 1)^{5 x + 2} = (2 x^{2} - 1)^{x^{2} + 6}

x = 1, x = - 1, x = 4

Solution steps

(2 x^{2} - 1)^{5 x + 2} = (2 x^{2} - 1)^{x^{2} + 6}

Apply exponent rules

(5 x + 2) ln (2 x^{2} - 1) = (x^{2} + 6) ln (2 x^{2} - 1)

Solve

(5 x + 2) ln (2 x^{2} - 1) = (x^{2} + 6) ln (2 x^{2} - 1) : x = 1, x = - 1, x = 4

x = 1, x = - 1, x = 4

9^{x + 2} = 2 7^{x}

x, (19) \cdot y = (c_{1} + c_{2} \cdot x) \cdot e^{x}

(5 + 24)^{x} + (5 - 24)^{x} = 10

7^{1 - x} = 4 9^{3 x + 1}

x, e^{y} = 2^{x}

What is the answer to (2x^2-1)^{5x+2}=(2x^2-1)^{x^2+6} ?
The answer to (2x^2-1)^{5x+2}=(2x^2-1)^{x^2+6} is x=1,x=-1,x=4
Solve for x: (2x^2-1)^{5x+2}=(2x^2-1)^{x^2+6}
The solution is x=1,x=-1,x=4