What is the answer to 7^{1-x}=49^{3x+1} ?

The answer to 7^{1-x}=49^{3x+1} is x=-1/7

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

7^{1-x}=49^{3x+1}

7^{1 - x} = 4 9^{3 x + 1}

x = - \frac{1}{7}

Decimal Notation

x = - 0.14285 \dots

Solution steps

7^{1 - x} = 4 9^{3 x + 1}

Apply exponent rules

1 - x = 2 (3 x + 1)

Solve

1 - x = 2 (3 x + 1) : x = - \frac{1}{7}

x = - \frac{1}{7}

x, e^{y} = 2^{x}

2^{2 x} - 2^{x + 1} = 8

9^{x} = 3^{x} - 3

x, b = a \cdot (1 + \frac{63}{100})^{x}

3^{x} + x - 4 = 0

What is the answer to 7^{1-x}=49^{3x+1} ?
The answer to 7^{1-x}=49^{3x+1} is x=-1/7
Solve for x: 7^{1-x}=49^{3x+1}
The solution is x=-1/7