What is the answer to 2*3^{1/(2*x+2)}=23.43 ?

The answer to 2*3^{1/(2*x+2)}=23.43 is x=(ln(3)-2ln(11.715))/(2ln(11.715))

Solve for x: 2*3^{1/(2*x+2)}=23.43

The solution is x=(ln(3)-2ln(11.715))/(2ln(11.715))

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2 \cdot 3^{\frac{1}{2 \cdot x + 2}} = 23.43

x = \frac{ln ( 3 ) - 2 ln ( 11.715 )}{2 ln ( 11.715 )}

Decimal Notation

x = - 0.77678 \dots

Solution steps

2 \cdot 3^{\frac{1}{2 x + 2}} = 23.43

Divide both sides by

2

3^{\frac{1}{2 x + 2}} = 11.715

Apply exponent rules

\frac{1}{2 x + 2} ln (3) = ln (11.715)

Solve

\frac{1}{2 x + 2} ln (3) = ln (11.715) : x = \frac{ln ( 3 ) - 2 ln ( 11.715 )}{2 ln ( 11.715 )}

x = \frac{ln ( 3 ) - 2 ln ( 11.715 )}{2 ln ( 11.715 )}

5^{2 x} = 62 5^{\frac{3}{4}}

2^{x - 2} + 2^{x} = 5

2^{x} = 0.125

x^{x} = (2^{20})

8^{2 x + 1} = 2^{x - 1}

What is the answer to 2*3^{1/(2*x+2)}=23.43 ?
The answer to 2*3^{1/(2*x+2)}=23.43 is x=(ln(3)-2ln(11.715))/(2ln(11.715))
Solve for x: 2*3^{1/(2*x+2)}=23.43
The solution is x=(ln(3)-2ln(11.715))/(2ln(11.715))