What is the answer to 8^{2x+1}=2^{x-1} ?

The answer to 8^{2x+1}=2^{x-1} is x=-4/5

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8^{2x+1}=2^{x-1}

8^{2 x + 1} = 2^{x - 1}

x = - \frac{4}{5}

Decimal Notation

x = - 0.8

Solution steps

8^{2 x + 1} = 2^{x - 1}

Apply exponent rules

3 (2 x + 1) = x - 1

Solve

3 (2 x + 1) = x - 1 : x = - \frac{4}{5}

x = - \frac{4}{5}

y, x^{x} + x^{y} = 81

4^{x} + 2 - 6 (2^{x} - 1) = 0

p, 2^{p} - 2^{q} = 48

3^{x} \cdot 9^{2 x + 1} = 81

m, 3^{m} - 2^{n} = 2

What is the answer to 8^{2x+1}=2^{x-1} ?
The answer to 8^{2x+1}=2^{x-1} is x=-4/5
Solve for x: 8^{2x+1}=2^{x-1}
The solution is x=-4/5