What is the answer to 3^x*9^{2x+1}=81 ?

The answer to 3^x*9^{2x+1}=81 is x= 2/5

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3^x*9^{2x+1}=81

3^{x} \cdot 9^{2 x + 1} = 81

x = \frac{2}{5}

Decimal Notation

x = 0.4

Solution steps

3^{x} \cdot 9^{2 x + 1} = 81

Apply exponent rules

x + 2 (2 x + 1) = 4

Solve

x + 2 (2 x + 1) = 4 : x = \frac{2}{5}

x = \frac{2}{5}

m, 3^{m} - 2^{n} = 2

3^{x + 2} + 3^{- x} = 10

1.2 1^{x} = 100

4^{- 6} x = 1 7^{x} + 4

4^{x} \cdot 4^{2 x - 8} = 64