What is the answer to 4^x=16^x+1 ?

The answer to 4^x=16^x+1 is No Solution for x\in\mathbb{R}

Solve for x: 4^x=16^x+1

The solution is No Solution for x\in\mathbb{R}

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Popular >

4^{x} = 1 6^{x} + 1

No Solution for x \in R

Solution steps

4^{x} = 1 6^{x} + 1

Apply exponent rules

4^{x} = (4^{x})^{2} + 1

Rewrite the equation with

4^{x} = u

u = (u)^{2} + 1

Solve

u = u^{2} + 1 :

No Solution for

u \in R

No Solution for x \in R

9^{x} \cdot 3^{3 x - 2} = 27

2^{x + 2} = 92 7^{\frac{x}{( x - 1 )}}

9 = e^{x}

1 7^{2 x} = - 3^{- x - 10}

e^{x} + x = 0

What is the answer to 4^x=16^x+1 ?
The answer to 4^x=16^x+1 is No Solution for x\in\mathbb{R}
Solve for x: 4^x=16^x+1
The solution is No Solution for x\in\mathbb{R}