What is the answer to 17^{2x}=-3^{-x-10} ?

The answer to 17^{2x}=-3^{-x-10} is x=(Undefined)/(2ln(17))

Solve for x: 17^{2x}=-3^{-x-10}

The solution is x=(Undefined)/(2ln(17))

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1 7^{2 x} = - 3^{- x - 10}

x = \frac{Undefined}{2 ln ( 17 )}

Solution steps

1 7^{2 x} = - 3^{- x - 10}

Apply exponent rules

2 x ln (17) = ln (- 1) + (- x - 10) ln (3)

Solve

2 x ln (17) = ln (- 1) + (- x - 10) ln (3) : x = \frac{Undefined}{2 ln ( 17 )}

x = \frac{Undefined}{2 ln ( 17 )}

e^{x} + x = 0

4^{n} = 2

5. 3^{x} = 2

5^{2 x + 1} - 5^{2 x} = 500

0. 6^{x - 3} = 3. 2^{x + 4}

What is the answer to 17^{2x}=-3^{-x-10} ?
The answer to 17^{2x}=-3^{-x-10} is x=(Undefined)/(2ln(17))
Solve for x: 17^{2x}=-3^{-x-10}
The solution is x=(Undefined)/(2ln(17))