What is the answer to 3^{4x+3}=8^{-x+2} ?

The answer to 3^{4x+3}=8^{-x+2} is x=(6ln(2)-3ln(3))/(ln(648))

Solve for x: 3^{4x+3}=8^{-x+2}

The solution is x=(6ln(2)-3ln(3))/(ln(648))

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

3^{4 x + 3} = 8^{- x + 2}

x = \frac{6 ln ( 2 ) - 3 ln ( 3 )}{ln ( 648 )}

Decimal Notation

x = 0.13331 \dots

Solution steps

3^{4 x + 3} = 8^{- x + 2}

Apply exponent rules

(4 x + 3) ln (3) = (- x + 2) ln (8)

Solve

(4 x + 3) ln (3) = (- x + 2) ln (8) : x = \frac{6 ln ( 2 ) - 3 ln ( 3 )}{ln ( 648 )}

x = \frac{6 ln ( 2 ) - 3 ln ( 3 )}{ln ( 648 )}

12 (2)^{x} = 15 (4)^{2} x - 3

4^{x + 3} = 7

(6 4^{x^{2} - 2 x}) (1 6^{x - 5}) = 1

(x + 2) e^{x} = 1

t, a (t) = a_{0} \cdot e^{- 0.025 t}

What is the answer to 3^{4x+3}=8^{-x+2} ?
The answer to 3^{4x+3}=8^{-x+2} is x=(6ln(2)-3ln(3))/(ln(648))
Solve for x: 3^{4x+3}=8^{-x+2}
The solution is x=(6ln(2)-3ln(3))/(ln(648))