What is the answer to 17^{x-2}=4^{4x} ?

The answer to 17^{x-2}=4^{4x} is x=(2ln(17))/(ln(17)-8ln(2))

Solve for x: 17^{x-2}=4^{4x}

The solution is x=(2ln(17))/(ln(17)-8ln(2))

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1 7^{x - 2} = 4^{4 x}

x = \frac{2 ln ( 17 )}{ln ( 17 ) - 8 ln ( 2 )}

Decimal Notation

x = - 2.08941 \dots

Solution steps

1 7^{x - 2} = 4^{4 x}

Apply exponent rules

(x - 2) ln (17) = 4 x ln (4)

Solve

(x - 2) ln (17) = 4 x ln (4) : x = \frac{2 ln ( 17 )}{ln ( 17 ) - 8 ln ( 2 )}

x = \frac{2 ln ( 17 )}{ln ( 17 ) - 8 ln ( 2 )}

3^{3 x - 2} = 12

e^{2 k} - e^{k} - 6 = 0

4^{x} = 2^{x + 1} + 3

(7)^{- 1} \cdot (7)^{3 k + 2} = \frac{( 7 ) ^{15}}{( ( 7 ) ^{8} )}

9^{n + 1} - 9^{n} = 72

What is the answer to 17^{x-2}=4^{4x} ?
The answer to 17^{x-2}=4^{4x} is x=(2ln(17))/(ln(17)-8ln(2))
Solve for x: 17^{x-2}=4^{4x}
The solution is x=(2ln(17))/(ln(17)-8ln(2))