What is the answer to (7)^{-1}*(7)^{3k+2}=((7)^{15})/(((7)^8)) ?

The answer to (7)^{-1}*(7)^{3k+2}=((7)^{15})/(((7)^8)) is k=2

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(7)^{-1}*(7)^{3k+2}=((7)^{15})/(((7)^8))

(7)^{- 1} \cdot (7)^{3 k + 2} = \frac{( 7 ) ^{15}}{( ( 7 ) ^{8} )}

k = 2

Solution steps

(7)^{- 1} (7)^{3 k + 2} = \frac{( 7 ) ^{15}}{( ( 7 ) ^{8} )}

Apply exponent rules

3 k + 1 = 7

Solve

3 k + 1 = 7 : k = 2

k = 2

9^{n + 1} - 9^{n} = 72

x, (\frac{x}{10}) - a \cdot e^{- \frac{x}{( r \cdot t )}} = 0

n = 1 + (\frac{9}{10})^{n}

(\frac{3}{5})^{1 - 2 x} = \frac{417}{27}

2^{2} x + 3 + 2^{x} + 3 = 1 + 2^{x}

What is the answer to (7)^{-1}*(7)^{3k+2}=((7)^{15})/(((7)^8)) ?
The answer to (7)^{-1}*(7)^{3k+2}=((7)^{15})/(((7)^8)) is k=2
Solve for k: (7)^{-1}*(7)^{3k+2}=((7)^{15})/(((7)^8))
The solution is k=2